Question: The average of $ 4z - 3 $, $ 2z + 5 $, and $ z + 1 $ is 6. Solve for $ z $.

Solving for $ z $: Understanding the Average of Three Expressions
Understanding how to calculate the average of expressions is a key skill in algebra. One common problem students encounter is finding a variable when the average of multiple expressions is known. In this article, we’ll explore how to solve for $ z $ when the average of $ 4z - 3 $, $ 2z + 5 $, and $ z + 1 $ equals 6.
What does the average mean?
The average of three numbers is the sum divided by 3. So, if the average of $ 4z - 3 $, $ 2z + 5 $, and $ z + 1 $ is 6, we can write:
$$ rac{(4z - 3) + (2z + 5) + (z + 1)}{3} = 6 $$
Step-by-step solution
Step 1: Combine the expressions in the numerator
First, add the three expressions together:
$$ (4z - 3) + (2z + 5) + (z + 1) $$
Group like terms:
- Terms with $ z $: $ 4z + 2z + z = 7z $
- Constant terms: $ -3 + 5 + 1 = 3 $
So the total expression becomes:
$$ 7z + 3 $$
Now the equation looks like:
$$ rac{7z + 3}{3} = 6 $$
Step 2: Eliminate the denominator
Multiply both sides of the equation by 3:
$$ 7z + 3 = 18 $$
Step 3: Solve for $ z $
Subtract 3 from both sides:
$$ 7z = 15 $$
Divide both sides by 7:
$$ z = rac{15}{7} $$
Final Answer
$$ z = rac{15}{7} $$
Why this matters
Knowing how to set up and solve average problems helps build strong foundations in algebra. This skill is especially useful in real-world applications, such as calculating averages in data analysis, test scores, or financial planning—where finding an unknown variable based on an average is a common task.
Mastering this problem not only helps with equations but also improves logical reasoning and equation-solving confidence.
Summary
- The average of $ 4z - 3 $, $ 2z + 5 $, and $ z + 1 $ is $ rac{7z + 3}{3} $
- Set $ rac{7z + 3}{3} = 6 $
- Solve for $ z $ to get $ z = rac{15}{7} $
Start solving algebraic word problems with clarity—understanding averages is a vital step!









